Staircase patterns of # in C++

As a mental exercise, I just wanted to practice coding this part. This is mainly taught in programming courses to sort of explain how nested loops work. Here's a program that prints different staircase patterns based on a given integer number, N.

I personally would recommend you to try printing and forming the logic to print patterns by yourself first and then try looking up the solution.

Pattern #1

#
##
###
####
#####

 void progressiveStaircase(int number)
{
    for (int i = 0; i < number; i++)
    {
        for (int j = 0; j <= i; j++)
        {
            cout << "#";
        }
        cout << endl;
    }
}

Pattern #2

#####
####
###
##
#

 void reverseStaircase(int number)
{
    for (int i = 0; i < number; i++)
    {
        for (int j = i; j < number; j++)
        {
            cout << "#";
        }
        cout << endl;
    }
}

Pattern #3  

         #
       ##
    ###
  ####
#####

 void progressiveStaircaseRight(int number)
{

    for (int i = 0; i < number; i++)
    {
        for (int j = 0; j < number; j++)
        {
            if (i + j >= number - 1)
            {
                cout << "#";
            }
            else
            {
                cout << " ";
            }
        }
        cout << endl;
    }

}

Pattern #4 

#####
  ####
   ###
    ##
      #

 void progressiveStaircaseLeft(int number)
{

    for (int i = 0; i < number; i++)
    {
        for (int j = 0; j < number; j++)
        {
            if (i <= j)
            {
                cout << "#";
            }
            else
            {
                cout << " ";
            }
        }
        cout << endl;
    }

Pattern #5 - Pyramid

        #

      ###

    #####

  #######

#########

 void pyramid(int number)
{

    int row = number;
    number = number * 2;
    if (number % 2 == 0)
    { // normalizing number so has equal amount of number on both sides.
        number = number + 1;
    }
    int mid = number / 2; // not adding 1 because loop starts from 0. 5= 5/2= 2 = 0 1 2 3 4 = 2 mid
    cout << "row=" << row << " column=" << number << " mid=" << mid << endl;
    for (int i = 0; i < row; i++)
    {
        for (int j = 0; j < number; j++)
        {
            if (j <= mid + i && j >= mid - i)
            {
                cout << "#";
            }
            else
            {
                cout << " ";
            }
        }
        cout << endl;
    }
}

Output of all patterns altogether :

You can download the full source code from there : Staircase#.cpp